(1+i)z-(1-i)=4

Solution for (1+i)z-(1-i)=4 equation:

Simplifying
(1 + i) * z + -1(1 + -1i) = 4

Reorder the terms for easier multiplication:
z(1 + i) + -1(1 + -1i) = 4
(1 * z + i * z) + -1(1 + -1i) = 4

Reorder the terms:
(iz + 1z) + -1(1 + -1i) = 4
(iz + 1z) + -1(1 + -1i) = 4
iz + 1z + (1 * -1 + -1i * -1) = 4
iz + 1z + (-1 + 1i) = 4

Reorder the terms:
-1 + 1i + iz + 1z = 4

Solving
-1 + 1i + iz + 1z = 4

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1i + iz + 1 + 1z = 4 + 1

Reorder the terms:
-1 + 1 + 1i + iz + 1z = 4 + 1

Combine like terms: -1 + 1 = 0
0 + 1i + iz + 1z = 4 + 1
1i + iz + 1z = 4 + 1

Combine like terms: 4 + 1 = 5
1i + iz + 1z = 5

Add '-1z' to each side of the equation.
1i + iz + 1z + -1z = 5 + -1z

Combine like terms: 1z + -1z = 0
1i + iz + 0 = 5 + -1z
1i + iz = 5 + -1z

Reorder the terms:
-5 + 1i + iz + z = 5 + -1z + -5 + z

Reorder the terms:
-5 + 1i + iz + z = 5 + -5 + -1z + z

Combine like terms: 5 + -5 = 0
-5 + 1i + iz + z = 0 + -1z + z
-5 + 1i + iz + z = -1z + z

Combine like terms: -1z + z = 0
-5 + 1i + iz + z = 0

The solution to this equation could not be determined.