(1+i)(2+3i)(4-3i)=0

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Solution for (1+i)(2+3i)(4-3i)=0 equation: 



(1+i)(2+3i)(4-3i)=0

We add all the numbers together, and all the variables

(i+1)(3i+2)(-3i+4)=0

We multiply parentheses ..

(+3i^2+2i+3i+2)(-3i+4)=0

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