(1+cosx)(1-cosx)=0

Solution for (1+cosx)(1-cosx)=0 equation:

Simplifying
(1 + cosx)(1 + -1cosx) = 0

Multiply (1 + cosx) * (1 + -1cosx)
(1(1 + -1cosx) + cosx(1 + -1cosx)) = 0
((1 * 1 + -1cosx * 1) + cosx(1 + -1cosx)) = 0
((1 + -1cosx) + cosx(1 + -1cosx)) = 0
(1 + -1cosx + (1 * cosx + -1cosx * cosx)) = 0
(1 + -1cosx + (1cosx + -1c2o2s2x2)) = 0

Combine like terms: -1cosx + 1cosx = 0
(1 + 0 + -1c2o2s2x2) = 0
(1 + -1c2o2s2x2) = 0

Solving
1 + -1c2o2s2x2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c2o2s2x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c2o2s2x2 = 0 + -1
-1c2o2s2x2 = 0 + -1

Combine like terms: 0 + -1 = -1
-1c2o2s2x2 = -1

Divide each side by '-1o2s2x2'.
c2 = o-2s-2x-2

Simplifying
c2 = o-2s-2x-2

Take the square root of each side:
c = {-1o-1s-1x-1, o-1s-1x-1}