(1+4p)(4p-1)(p+2)=0

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Solution for (1+4p)(4p-1)(p+2)=0 equation: 


Simplifying
(1 + 4p)(4p + -1)(p + 2) = 0

Reorder the terms:
(1 + 4p)(-1 + 4p)(p + 2) = 0

Reorder the terms:
(1 + 4p)(-1 + 4p)(2 + p) = 0

Multiply (1 + 4p) * (-1 + 4p)
(1(-1 + 4p) + 4p * (-1 + 4p))(2 + p) = 0
((-1 * 1 + 4p * 1) + 4p * (-1 + 4p))(2 + p) = 0
((-1 + 4p) + 4p * (-1 + 4p))(2 + p) = 0
(-1 + 4p + (-1 * 4p + 4p * 4p))(2 + p) = 0
(-1 + 4p + (-4p + 16p2))(2 + p) = 0

Combine like terms: 4p + -4p = 0
(-1 + 0 + 16p2)(2 + p) = 0
(-1 + 16p2)(2 + p) = 0

Multiply (-1 + 16p2) * (2 + p)
(-1(2 + p) + 16p2 * (2 + p)) = 0
((2 * -1 + p * -1) + 16p2 * (2 + p)) = 0
((-2 + -1p) + 16p2 * (2 + p)) = 0
(-2 + -1p + (2 * 16p2 + p * 16p2)) = 0
(-2 + -1p + (32p2 + 16p3)) = 0
(-2 + -1p + 32p2 + 16p3) = 0

Solving
-2 + -1p + 32p2 + 16p3 = 0

Solving for variable 'p'.

The solution to this equation could not be determined.

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