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(1+3x/4)=(5/2)
We move all terms to the left:
(1+3x/4)-((5/2))=0
We add all the numbers together, and all the variables
(3x/4+1)-((+5/2))=0
We get rid of parentheses
3x/4+1-((+5/2))=0
We calculate fractions
6x^2/()+1+()/()=0
We add all the numbers together, and all the variables
6x^2/()+2=0
We multiply all the terms by the denominator
6x^2+2*()=0
We add all the numbers together, and all the variables
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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