(1+2j)(1-2j)=1

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Solution for (1+2j)(1-2j)=1 equation: 



(1+2j)(1-2j)=1

We move all terms to the left:

(1+2j)(1-2j)-(1)=0

We add all the numbers together, and all the variables

(2j+1)(-2j+1)-1=0

We multiply parentheses ..

(-4j^2+2j-2j+1)-1=0

We get rid of parentheses

-4j^2+2j-2j+1-1=0

We add all the numbers together, and all the variables

-4j^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$j=\frac{-b}{2a}=\frac{0}{-8}=0$

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