(1+2i)z=3z-i

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Solution for (1+2i)z=3z-i equation:


Simplifying
(1 + 2i) * z = 3z + -1i

Reorder the terms for easier multiplication:
z(1 + 2i) = 3z + -1i
(1 * z + 2i * z) = 3z + -1i

Reorder the terms:
(2iz + 1z) = 3z + -1i
(2iz + 1z) = 3z + -1i

Reorder the terms:
2iz + 1z = -1i + 3z

Solving
2iz + 1z = -1i + 3z

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'i' to each side of the equation.
2iz + i + 1z = -1i + i + 3z

Reorder the terms:
i + 2iz + 1z = -1i + i + 3z

Combine like terms: -1i + i = 0
i + 2iz + 1z = 0 + 3z
i + 2iz + 1z = 3z

Add '-1z' to each side of the equation.
i + 2iz + 1z + -1z = 3z + -1z

Combine like terms: 1z + -1z = 0
i + 2iz + 0 = 3z + -1z
i + 2iz = 3z + -1z

Combine like terms: 3z + -1z = 2z
i + 2iz = 2z

Combine like terms: 2z + -2z = 0
i + 2iz + -2z = 0

The solution to this equation could not be determined.

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