(1+2i)z=2+5i

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Solution for (1+2i)z=2+5i equation:


Simplifying
(1 + 2i) * z = 2 + 5i

Reorder the terms for easier multiplication:
z(1 + 2i) = 2 + 5i
(1 * z + 2i * z) = 2 + 5i

Reorder the terms:
(2iz + 1z) = 2 + 5i
(2iz + 1z) = 2 + 5i

Solving
2iz + 1z = 2 + 5i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-5i' to each side of the equation.
2iz + -5i + 1z = 2 + 5i + -5i

Reorder the terms:
-5i + 2iz + 1z = 2 + 5i + -5i

Combine like terms: 5i + -5i = 0
-5i + 2iz + 1z = 2 + 0
-5i + 2iz + 1z = 2

Add '-1z' to each side of the equation.
-5i + 2iz + 1z + -1z = 2 + -1z

Combine like terms: 1z + -1z = 0
-5i + 2iz + 0 = 2 + -1z
-5i + 2iz = 2 + -1z

Reorder the terms:
-2 + -5i + 2iz + z = 2 + -1z + -2 + z

Reorder the terms:
-2 + -5i + 2iz + z = 2 + -2 + -1z + z

Combine like terms: 2 + -2 = 0
-2 + -5i + 2iz + z = 0 + -1z + z
-2 + -5i + 2iz + z = -1z + z

Combine like terms: -1z + z = 0
-2 + -5i + 2iz + z = 0

The solution to this equation could not be determined.

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