(1+2i)-(-8-i)=0

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Solution for (1+2i)-(-8-i)=0 equation:


Simplifying
(1 + 2i) + -1(-8 + -1i) = 0

Remove parenthesis around (1 + 2i)
1 + 2i + -1(-8 + -1i) = 0
1 + 2i + (-8 * -1 + -1i * -1) = 0
1 + 2i + (8 + 1i) = 0

Reorder the terms:
1 + 8 + 2i + 1i = 0

Combine like terms: 1 + 8 = 9
9 + 2i + 1i = 0

Combine like terms: 2i + 1i = 3i
9 + 3i = 0

Solving
9 + 3i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 3i = 0 + -9

Combine like terms: 9 + -9 = 0
0 + 3i = 0 + -9
3i = 0 + -9

Combine like terms: 0 + -9 = -9
3i = -9

Divide each side by '3'.
i = -3

Simplifying
i = -3

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