(1)3(x-2)=2-4(x+3)

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Solution for (1)3(x-2)=2-4(x+3) equation: 



(1)3(x-2)=2-4(x+3)

We move all terms to the left:

(1)3(x-2)-(2-4(x+3))=0

We multiply parentheses

13x-(2-4(x+3))-26=0



We calculate terms in parentheses: -(2-4(x+3)), so:

2-4(x+3)

determiningTheFunctionDomain
-4(x+3)+2

We multiply parentheses

-4x-12+2

We add all the numbers together, and all the variables

-4x-10

Back to the equation:

-(-4x-10)



We get rid of parentheses

13x+4x+10-26=0

We add all the numbers together, and all the variables

17x-16=0

We move all terms containing x to the left, all other terms to the right

17x=16

x=16/17

x=16/17

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