(1)/(4)z+9=-1

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Solution for (1)/(4)z+9=-1 equation: 



(1)/(4)z+9=-1

We move all terms to the left:

(1)/(4)z+9-(-1)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

1/4z+10=0

We multiply all the terms by the denominator


10*4z+1=0

Wy multiply elements

40z+1=0

We move all terms containing z to the left, all other terms to the right

40z=-1

z=-1/40

z=-1/40

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