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(1)/(4)x-2=-3x-15
We move all terms to the left:
(1)/(4)x-2-(-3x-15)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
1/4x+3x+15-2=0
We multiply all the terms by the denominator
3x*4x+15*4x-2*4x+1=0
Wy multiply elements
12x^2+60x-8x+1=0
We add all the numbers together, and all the variables
12x^2+52x+1=0
a = 12; b = 52; c = +1;
Δ = b2-4ac
Δ = 522-4·12·1
Δ = 2656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2656}=\sqrt{16*166}=\sqrt{16}*\sqrt{166}=4\sqrt{166}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-4\sqrt{166}}{2*12}=\frac{-52-4\sqrt{166}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+4\sqrt{166}}{2*12}=\frac{-52+4\sqrt{166}}{24} $
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