(1)/(4)(x+4x)+12=(1)/(2)(2-x)+10

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Solution for (1)/(4)(x+4x)+12=(1)/(2)(2-x)+10 equation: 



(1)/(4)(x+4x)+12=(1)/(2)(2-x)+10

We move all terms to the left:

(1)/(4)(x+4x)+12-((1)/(2)(2-x)+10)=0



Domain of the equation: 4(x+4x)!=0

x∈R





Domain of the equation: 2(2-x)+10)!=0

x∈R



We add all the numbers together, and all the variables

1/4(+5x)-(1/2(-1x+2)+10)+12=0

We calculate fractions


(2x(-)/(4(+5x)*2(-1x+2))+(-4x0/(4(+5x)*2(-1x+2))+12=0

We can not solve this equation

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