(1)/(4)(5b+11)=19

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Solution for (1)/(4)(5b+11)=19 equation: 



(1)/(4)(5b+11)=19

We move all terms to the left:

(1)/(4)(5b+11)-(19)=0



Domain of the equation: 4(5b+11)!=0

b∈R



We multiply all the terms by the denominator


-19*4(5b+11)+1=0

Wy multiply elements

-76b(5+1=0

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