(1)/(3)x+3=26+(6)/(18)x-23

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Solution for (1)/(3)x+3=26+(6)/(18)x-23 equation: 



(1)/(3)x+3=26+(6)/(18)x-23

We move all terms to the left:

(1)/(3)x+3-(26+(6)/(18)x-23)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 18x-23)!=0

x∈R



We add all the numbers together, and all the variables

1/3x-(6/18x+3)+3=0

We get rid of parentheses

1/3x-6/18x-3+3=0

We calculate fractions


18x/54x^2+(-18x)/54x^2-3+3=0

We add all the numbers together, and all the variables

18x/54x^2+(-18x)/54x^2=0

We multiply all the terms by the denominator


18x+(-18x)=0

We get rid of parentheses

18x-18x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

Równanie nie ma rozwiązania

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