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(1)/(3)(6-15x)=-2+4x
We move all terms to the left:
(1)/(3)(6-15x)-(-2+4x)=0
Domain of the equation: 3(6-15x)!=0We add all the numbers together, and all the variables
x∈R
1/3(-15x+6)-(4x-2)=0
We get rid of parentheses
1/3(-15x+6)-4x+2=0
We multiply all the terms by the denominator
-4x*3(-15x+6)+2*3(-15x+6)+1=0
Wy multiply elements
-12x^2(-+6x(-+1=0
We use the square of the difference formula
-12x^2(-6x(-1=0
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