(1)/(3)(12x-6)-2x+28=-4(3x+9)+6

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Solution for (1)/(3)(12x-6)-2x+28=-4(3x+9)+6 equation: 



(1)/(3)(12x-6)-2x+28=-4(3x+9)+6

We move all terms to the left:

(1)/(3)(12x-6)-2x+28-(-4(3x+9)+6)=0



Domain of the equation: 3(12x-6)!=0

x∈R



We add all the numbers together, and all the variables

-2x+1/3(12x-6)-(-4(3x+9)+6)+28=0

We multiply all the terms by the denominator


-2x*3(12x-6)-((-4(3x+9)+6))*3(12x-6)+28*3(12x-6)+1=0



We calculate terms in parentheses: -((-4(3x+9)+6))*3(12x-6), so:

(-4(3x+9)+6))*3(12x-6



Wy multiply elements

-6x^2(1-((-4(3x+9)+6))*3(12x-6)+84x(1+1=0

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