(1)/(2x-8)+1/(x-4)

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Solution for (1)/(2x-8)+1/(x-4) equation: 


D( x )

2*x-8 = 0

x-4 = 0

2*x-8 = 0

2*x-8 = 0

2*x-8 = 0 // + 8

2*x = 8 // : 2

x = 8/2

x = 4

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

1/(2*x-8)+1/(x-4) = 0

(1*(x-4))/((2*x-8)*(x-4))+(1*(2*x-8))/((2*x-8)*(x-4)) = 0

1*(x-4)+1*(2*x-8) = 0

3*x-12 = 0

(3*x-12)/((2*x-8)*(x-4)) = 0

(3*x-12)/((2*x-8)*(x-4)) = 0 // * (2*x-8)*(x-4)

3*x-12 = 0

3*x-12 = 0 // + 12

3*x = 12 // : 3

x = 12/3

x = 4

x in { 4} 

x belongs to the empty set

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