(1)/(2)x+10=(1)/(4)x+54

Solution for (1)/(2)x+10=(1)/(4)x+54 equation:

(1)/(2)x+10=(1)/(4)x+54

We move all terms to the left:

(1)/(2)x+10-((1)/(4)x+54)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x+54)!=0

x∈R


We get rid of parentheses

1/2x-1/4x-54+10=0

We calculate fractions


4x/8x^2+(-2x)/8x^2-54+10=0

We add all the numbers together, and all the variables

4x/8x^2+(-2x)/8x^2-44=0

We multiply all the terms by the denominator


4x+(-2x)-44*8x^2=0

Wy multiply elements

-352x^2+4x+(-2x)=0

We get rid of parentheses

-352x^2+4x-2x=0

We add all the numbers together, and all the variables

-352x^2+2x=0

a = -352; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-352)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-352}=\frac{-4}{-704}
=1/176
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-352}=\frac{0}{-704}
=0
$