(1)/(2)(y-8)=(1)/(4)y-2

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Solution for (1)/(2)(y-8)=(1)/(4)y-2 equation: 



(1)/(2)(y-8)=(1)/(4)y-2

We move all terms to the left:

(1)/(2)(y-8)-((1)/(4)y-2)=0



Domain of the equation: 2(y-8)!=0

y∈R





Domain of the equation: 4y-2)!=0

y∈R



We get rid of parentheses

1/2(y-8)-1/4y+2=0

We calculate fractions


4y/(8y^2-64y)+(-2yy/(8y^2-64y)+2=0

We calculate fractions

We do not support eypression: y^3

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