(1)/(2)(p+6)=(7)/(2)(3-p)

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Solution for (1)/(2)(p+6)=(7)/(2)(3-p) equation: 



(1)/(2)(p+6)=(7)/(2)(3-p)

We move all terms to the left:

(1)/(2)(p+6)-((7)/(2)(3-p))=0



Domain of the equation: 2(p+6)!=0

p∈R





Domain of the equation: 2(3-p))!=0

p∈R



We add all the numbers together, and all the variables

1/2(p+6)-(7/2(-1p+3))=0

We calculate fractions


(2p(-)/(2(p+6)*2(-1p+3)))+(-14pp/(2(p+6)*2(-1p+3)))=0



We calculate terms in parentheses: +(2p(-)/(2(p+6)*2(-1p+3))), so:

2p(-)/(2(p+6)*2(-1p+3))

We add all the numbers together, and all the variables

2p0/(2(p+6)*2(-1p+3))

We multiply all the terms by the denominator


2p0

We add all the numbers together, and all the variables

2p

Back to the equation:

+(2p)





We calculate terms in parentheses: +(-14pp/(2(p+6)*2(-1p+3))), so:

-14pp/(2(p+6)*2(-1p+3))

We multiply all the terms by the denominator


-14pp

Back to the equation:

+(-14pp)



We get rid of parentheses

2p-14pp=0

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