(1)/(2)(c-3)=19-c

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Solution for (1)/(2)(c-3)=19-c equation: 



(1)/(2)(c-3)=19-c

We move all terms to the left:

(1)/(2)(c-3)-(19-c)=0



Domain of the equation: 2(c-3)!=0

c∈R



We add all the numbers together, and all the variables

1/2(c-3)-(-1c+19)=0

We get rid of parentheses

1/2(c-3)+1c-19=0

We multiply all the terms by the denominator


1c*2(c-3)-19*2(c-3)+1=0

Wy multiply elements

2c^2(c-38c(c+1=0

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