(0.6+x)(0.4+x)/(0.8-x)(0.4-x)=3

Solution for (0.6+x)(0.4+x)/(0.8-x)(0.4-x)=3 equation:

(0.6+x)(0.4+x)/(0.8-x)(0.4-x)=3

We move all terms to the left:

(0.6+x)(0.4+x)/(0.8-x)(0.4-x)-(3)=0


Domain of the equation: (0.8-x)(0.4-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.4-x!=-0.8

x∈R


We add all the numbers together, and all the variables

(x+0.6)(x+0.4)/(-1x+0.8)(-1x+0.4)-3=0

We multiply parentheses ..

(+x^2+0.4x+0.6x+0.24)/(-1x+0.8)(-1x+0.4)-3=0

We multiply all the terms by the denominator


(+x^2+0.4x+0.6x+0.24)-3*(-1x+0.8)(-1x+0.4)=0

We get rid of parentheses

x^2+0.4x+0.6x-3*(-1x+0.8)(-1x+0.4)+0.24=0

We multiply parentheses ..

x^2-3*(+x^2-0.4x-0.8x+0.32)+0.4x+0.6x+0.24=0

We add all the numbers together, and all the variables

x^2-3*(+x^2-0.4x-0.8x+0.32)+x+0.24=0

We multiply parentheses

x^2-3x^2-0x-0x+x-0.96+0.24=0

We add all the numbers together, and all the variables

-2x^2-1x-0.72=0

a = -2; b = -1; c = -0.72;
Δ = b2-4ac
Δ = -12-4·(-2)·(-0.72)
Δ = -4.76
Delta is less than zero, so there is no solution for the equation