(0.20)(10)=(0.05)(10-x)+(0.40)(10-x)

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Solution for (0.20)(10)=(0.05)(10-x)+(0.40)(10-x) equation: 



(0.20)(10)=(0.05)(10-x)+(0.40)(10-x)

We move all terms to the left:

(0.20)(10)-((0.05)(10-x)+(0.40)(10-x))=0

We add all the numbers together, and all the variables

-((0.05)(-1x+10)+(0.4)(-1x+10))+(0.2)10=0

We add all the numbers together, and all the variables

-((0.05)(-1x+10)+(0.4)(-1x+10))+2=0

We multiply parentheses ..

-((-0.05x+0.5)+(0.4)(-1x+10))+2=0



We calculate terms in parentheses: -((-0.05x+0.5)+(0.4)(-1x+10)), so:

(-0.05x+0.5)+(0.4)(-1x+10)

We get rid of parentheses

-0.05x+(0.4)(-1x+10)+0.5

We multiply parentheses ..

-0.05x+(-0.4x+4)+0.5

We get rid of parentheses

-0.05x-0.4x+4+0.5

We add all the numbers together, and all the variables

-0.45x+4.5

Back to the equation:

-(-0.45x+4.5)



We get rid of parentheses

0.45x-4.5+2=0

We add all the numbers together, and all the variables

0.45x-2.5=0

We move all terms containing x to the left, all other terms to the right

0.45x=2.5

x=2.5/0.45

x=5+0.25/0.45

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