(0.1x+60)(3x+36)=180

Solution for (0.1x+60)(3x+36)=180 equation:

(0.1x+60)(3x+36)=180

We move all terms to the left:

(0.1x+60)(3x+36)-(180)=0

We multiply parentheses ..

(+0x^2+0x+180x+2160)-180=0

We get rid of parentheses

0x^2+0x+180x+2160-180=0

We add all the numbers together, and all the variables

x^2+181x+1980=0

a = 1; b = 181; c = +1980;
Δ = b2-4ac
Δ = 1812-4·1·1980
Δ = 24841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(181)-\sqrt{24841}}{2*1}=\frac{-181-\sqrt{24841}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(181)+\sqrt{24841}}{2*1}=\frac{-181+\sqrt{24841}}{2}
$