(0.1+1x)(0.1-1x)=0

Solution for (0.1+1x)(0.1-1x)=0 equation:

(0.1+1x)(0.1-1x)=0

We add all the numbers together, and all the variables

(x+0.1)(-1x+0.1)=0

We multiply parentheses ..

(-1x^2+0.1x-0.1x+0.01)=0

We get rid of parentheses

-1x^2+0.1x-0.1x+0.01=0

We add all the numbers together, and all the variables

-1x^2+0.01=0

a = -1; b = 0; c = +0.01;
Δ = b2-4ac
Δ = 02-4·(-1)·0.01
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.04}}{2*-1}=\frac{0-\sqrt{0.04}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.04}}{2*-1}=\frac{0+\sqrt{0.04}}{-2}
=\frac{\sqrt{}}{-2}
$