(0.005+x)x=(0.012)*(0.005-x)

Solution for (0.005+x)x=(0.012)*(0.005-x) equation:

(0.005+x)x=(0.012)(0.005-x)

We move all terms to the left:

(0.005+x)x-((0.012)(0.005-x))=0

We add all the numbers together, and all the variables

(x+0.005)x-((0.012)(-1x+0.005))=0

We multiply parentheses

x^2+0.005x-((0.012)(-1x+0.005))=0

We multiply parentheses ..

x^2+0.005x-((-0.012x+6.0E-5))=0


We calculate terms in parentheses: -((-0.012x+6.0E-5)), so:

(-0.012x+6.0E-5)

We add all the numbers together, and all the variables

(-0.012x+11.309690970754)

We get rid of parentheses

-0.012x+11.309690970754

Back to the equation:

-(-0.012x+11.309690970754)


We get rid of parentheses

x^2+0.005x+0.012x-11.309690970754=0

We add all the numbers together, and all the variables

x^2+0.017x-11.309690970754=0

a = 1; b = 0.017; c = -11.309690970754;
Δ = b2-4ac
Δ = 0.0172-4·1·(-11.309690970754)
Δ = 45.239052883016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.017)-\sqrt{45.239052883016}}{2*1}=\frac{-0.017-\sqrt{45.239052883016}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.017)+\sqrt{45.239052883016}}{2*1}=\frac{-0.017+\sqrt{45.239052883016}}{2}
$