(0,6x)/1=(40-2x)/(x+5)

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Solution for (0,6x)/1=(40-2x)/(x+5) equation: 



(0.6x)/1=(40-2x)/(x+5)

We move all terms to the left:

(0.6x)/1-((40-2x)/(x+5))=0



Domain of the equation: (x+5))!=0

x∈R



We add all the numbers together, and all the variables

(+0.6x)/1-((-2x+40)/(x+5))=0

We calculate fractions


((+0.6x)*(x+5)))/(1*(x+5)))+(-((-2x+40)*1)/(1*(x+5)))=0



We calculate terms in parentheses: +((+0.6x)*(x+5)))/(1*(x+5)))+(-((-2x+40)*1)/(1*(x+5))), so:

(+0.6x)*(x+5)))/(1*(x+5)))+(-((-2x+40)*1)/(1*(x+5))

determiningTheFunctionDomain
(+0.6x)*(x+5)))/(1*(x-2x+40)*1)/(1*(x+5)))+(-((+5))

We add all the numbers together, and all the variables

(+0.6x)*(x+5)))/(1*(-1x+40)*1)/(1*(x+5)))+(-(5)

We add all the numbers together, and all the variables

-1x+(+0.6x)*(x+5)))/(1*(+40)*1)/(1*(x

We calculate fractions


-1x+((+0.6x)*(x+5)))*(1*x/((1*(*(1*x+()/((1*(*(1*x

We can not solve this equation

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