(.5-x)(1.1-x)=0

Solution for (.5-x)(1.1-x)=0 equation:

(.5-x)(1.1-x)=0

We add all the numbers together, and all the variables

(-1x+0.5)(-1x+1.1)=0

We multiply parentheses ..

(+x^2-1.1x-0.5x+0.55)=0

We get rid of parentheses

x^2-1.1x-0.5x+0.55=0

We add all the numbers together, and all the variables

x^2-1.6x+0.55=0

a = 1; b = -1.6; c = +0.55;
Δ = b2-4ac
Δ = -1.62-4·1·0.55
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{0.36}}{2*1}=\frac{1.6-\sqrt{0.36}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{0.36}}{2*1}=\frac{1.6+\sqrt{0.36}}{2}
$