(.0224+2x)(.0224+2x)=0

Solution for (.0224+2x)(.0224+2x)=0 equation:

(.0224+2x)(.0224+2x)=0

We add all the numbers together, and all the variables

(2x+0.0224)(2x+0.0224)=0

We multiply parentheses ..

(+4x^2+0.0448x+0.0448x+0.00050176)=0

We get rid of parentheses

4x^2+0.0448x+0.0448x+0.00050176=0

We add all the numbers together, and all the variables

4x^2+0.0896x+0.00050176=0

a = 4; b = 0.0896; c = +0.00050176;
Δ = b2-4ac
Δ = 0.08962-4·4·0.00050176
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-0.0896}{8}=-0.0896/8$