(-y+2)=1/2y+2

Solution for (-y+2)=1/2y+2 equation:

(-y+2)=1/2y+2

We move all terms to the left:

(-y+2)-(1/2y+2)=0


Domain of the equation: 2y+2)!=0

y∈R


We add all the numbers together, and all the variables

(-1y+2)-(1/2y+2)=0

We get rid of parentheses

-1y-1/2y+2-2=0

We multiply all the terms by the denominator


-1y*2y+2*2y-2*2y-1=0

Wy multiply elements

-2y^2+4y-4y-1=0

We add all the numbers together, and all the variables

-2y^2-1=0

a = -2; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-2)·(-1)
Δ = -8
Delta is less than zero, so there is no solution for the equation