(-x-6)(-2x-8)=0

Solution for (-x-6)(-2x-8)=0 equation:

(-x-6)(-2x-8)=0

We add all the numbers together, and all the variables

(-1x-6)(-2x-8)=0

We multiply parentheses ..

(+2x^2+8x+12x+48)=0

We get rid of parentheses

2x^2+8x+12x+48=0

We add all the numbers together, and all the variables

2x^2+20x+48=0

a = 2; b = 20; c = +48;
Δ = b2-4ac
Δ = 202-4·2·48
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4}{2*2}=\frac{-24}{4}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4}{2*2}=\frac{-16}{4}
=-4
$