(-8m+1)(2m-7)=0

Solution for (-8m+1)(2m-7)=0 equation:

(-8m+1)(2m-7)=0

We multiply parentheses ..

(-16m^2+56m+2m-7)=0

We get rid of parentheses

-16m^2+56m+2m-7=0

We add all the numbers together, and all the variables

-16m^2+58m-7=0

a = -16; b = 58; c = -7;
Δ = b2-4ac
Δ = 582-4·(-16)·(-7)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-54}{2*-16}=\frac{-112}{-32}
=3+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+54}{2*-16}=\frac{-4}{-32}
=1/8
$