(-8c+16)-1/3(6+3c)=0

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Solution for (-8c+16)-1/3(6+3c)=0 equation: 



(-8c+16)-1/3(6+3c)=0



Domain of the equation: 3(6+3c)!=0

c∈R



We add all the numbers together, and all the variables

(-8c+16)-1/3(3c+6)=0

We get rid of parentheses

-8c-1/3(3c+6)+16=0

We multiply all the terms by the denominator


-8c*3(3c+6)+16*3(3c+6)-1=0

Wy multiply elements

-24c^2(3+48c(3-1=0

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