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(-8)=x-5/x+12
We move all terms to the left:
(-8)-(x-5/x+12)=0
Domain of the equation: x+12)!=0We add all the numbers together, and all the variables
x∈R
-(x-5/x+12)-8=0
We get rid of parentheses
-x+5/x-12-8=0
We multiply all the terms by the denominator
-x*x-12*x-8*x+5=0
We add all the numbers together, and all the variables
-20x-x*x+5=0
Wy multiply elements
-1x^2-20x+5=0
a = -1; b = -20; c = +5;
Δ = b2-4ac
Δ = -202-4·(-1)·5
Δ = 420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{420}=\sqrt{4*105}=\sqrt{4}*\sqrt{105}=2\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{105}}{2*-1}=\frac{20-2\sqrt{105}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{105}}{2*-1}=\frac{20+2\sqrt{105}}{-2} $
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