(-8)(-x-5)-2=-2(x+1)

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Solution for (-8)(-x-5)-2=-2(x+1) equation: 



(-8)(-x-5)-2=-2(x+1)

We move all terms to the left:

(-8)(-x-5)-2-(-2(x+1))=0

We add all the numbers together, and all the variables

(-8)(-1x-5)-(-2(x+1))-2=0

We multiply parentheses ..

(+8x+40)-(-2(x+1))-2=0



We calculate terms in parentheses: -(-2(x+1)), so:

-2(x+1)

We multiply parentheses

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

(8x+40)-(-2x-2)-2=0

We get rid of parentheses

8x+2x+40+2-2=0

We add all the numbers together, and all the variables

10x+40=0

We move all terms containing x to the left, all other terms to the right

10x=-40

x=-40/10

x=-4

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