(-7c-6)(2c+3)=0

Solution for (-7c-6)(2c+3)=0 equation:

(-7c-6)(2c+3)=0

We multiply parentheses ..

(-14c^2-21c-12c-18)=0

We get rid of parentheses

-14c^2-21c-12c-18=0

We add all the numbers together, and all the variables

-14c^2-33c-18=0

a = -14; b = -33; c = -18;
Δ = b2-4ac
Δ = -332-4·(-14)·(-18)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-9}{2*-14}=\frac{24}{-28}
=-6/7
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+9}{2*-14}=\frac{42}{-28}
=-1+1/2
$