(-7/u-5)=(5/4u-20)+2

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Solution for (-7/u-5)=(5/4u-20)+2 equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

-7/u-5 = (5/4)*u-20+2 // - (5/4)*u-20+2

20-((5/4)*u)-7/u-5-2 = 0

(-5/4)*u-7/u-5-2+20 = 0

13*u^0-5/4*u^1-7*u^-1 = 0

(13*u^1-5/4*u^2-7*u^0)/(u^1) = 0 // * u^2

u^1*(13*u^1-5/4*u^2-7*u^0) = 0

u^1

(-5/4)*u^2+13*u-7 = 0

(-5/4)*u^2+13*u-7 = 0

DELTA = 13^2-(-7*4*(-5/4))

DELTA = 134

DELTA > 0

u = (134^(1/2)-13)/(2*(-5/4)) or u = (-134^(1/2)-13)/(2*(-5/4))

u = -2/5*(134^(1/2)-13) or u = 2/5*(134^(1/2)+13)

u in { -2/5*(134^(1/2)-13), 2/5*(134^(1/2)+13)} 

u in { -2/5*(134^(1/2)-13), 2/5*(134^(1/2)+13) }

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