(-7/4)x+(3/4)=-15

Solution for (-7/4)x+(3/4)=-15 equation:

(-7/4)x+(3/4)=-15

We move all terms to the left:

(-7/4)x+(3/4)-(-15)=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(-7/4)x+(+3/4)-(-15)=0

We add all the numbers together, and all the variables

(-7/4)x+15+(+3/4)=0

We multiply parentheses

-7x^2+15+(+3/4)=0

We get rid of parentheses

-7x^2+15+3/4=0

We multiply all the terms by the denominator


-7x^2*4+3+15*4=0

We add all the numbers together, and all the variables

-7x^2*4+63=0

Wy multiply elements

-28x^2+63=0

a = -28; b = 0; c = +63;
Δ = b2-4ac
Δ = 02-4·(-28)·63
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*-28}=\frac{-84}{-56}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*-28}=\frac{84}{-56}
=-1+1/2
$