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sin(x)*(cos(x))^2
(1/(i*t+1))*((e^(i*t+1)-1)/(e-1))
3;4;1;2;3;5
x^ln(x)
63 = (-9/8)*x
| 8cos(x)=16 | | -(2x+8)=5x-1 | | 9z-6=8z | | 4n-6n=16 | | 22-2k=12 | | -3x+8=-43+3x | | 63=-9/8x | | 4c+5=c | | -30=2(x-6)-5x | | 3x+60+x+59=x^2-6x | | 4(-1+7x)=-172 | | 2.5-3=12 | | y=-48/x | | 7(u-1)=3u+3-2(-7u-1) | | 29=-6(3C+5) | | 4(5v)= | | 1x+7=2x+1x | | 3.35+x=3.62 | | 7+v=-5 | | -2.83+x=-2.73 | | 3x-6x-7= | | -8(-8+9)=-8 | | (2sinx+1)(2cosx-3)=0 | | -8(3+9)=-8 | | 7(12+n)=0 | | 7(9+3x)=0 | | -2=g-19 | | 8x-8-20x=-7x+7 | | -16.97+x=-16.63 | | -8(-6+9)=-8 | | 5y=-2x+(-15) | | 24=-8/5x |