(-6t-7)(-t-2)=0

Solution for (-6t-7)(-t-2)=0 equation:

(-6t-7)(-t-2)=0

We add all the numbers together, and all the variables

(-6t-7)(-1t-2)=0

We multiply parentheses ..

(+6t^2+12t+7t+14)=0

We get rid of parentheses

6t^2+12t+7t+14=0

We add all the numbers together, and all the variables

6t^2+19t+14=0

a = 6; b = 19; c = +14;
Δ = b2-4ac
Δ = 192-4·6·14
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-5}{2*6}=\frac{-24}{12}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+5}{2*6}=\frac{-14}{12}
=-1+1/6
$