(-6+3i)(2+i)=

Solution for (-6+3i)(2+i)= equation:

Simplifying
(-6 + 3i)(2 + i) = 0

Multiply (-6 + 3i) * (2 + i)
(-6(2 + i) + 3i * (2 + i)) = 0
((2 * -6 + i * -6) + 3i * (2 + i)) = 0
((-12 + -6i) + 3i * (2 + i)) = 0
(-12 + -6i + (2 * 3i + i * 3i)) = 0
(-12 + -6i + (6i + 3i2)) = 0

Combine like terms: -6i + 6i = 0
(-12 + 0 + 3i2) = 0
(-12 + 3i2) = 0

Solving
-12 + 3i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 3i2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 3i2 = 0 + 12
3i2 = 0 + 12

Combine like terms: 0 + 12 = 12
3i2 = 12

Divide each side by '3'.
i2 = 4

Simplifying
i2 = 4

Take the square root of each side:
i = {-2, 2}