(-5x-6)(-3x-5)=0

Solution for (-5x-6)(-3x-5)=0 equation:

(-5x-6)(-3x-5)=0

We multiply parentheses ..

(+15x^2+25x+18x+30)=0

We get rid of parentheses

15x^2+25x+18x+30=0

We add all the numbers together, and all the variables

15x^2+43x+30=0

a = 15; b = 43; c = +30;
Δ = b2-4ac
Δ = 432-4·15·30
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-7}{2*15}=\frac{-50}{30}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+7}{2*15}=\frac{-36}{30}
=-1+1/5
$