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(-5x-4)(8x-5)=0
We multiply parentheses ..
(-40x^2+25x-32x+20)=0
We get rid of parentheses
-40x^2+25x-32x+20=0
We add all the numbers together, and all the variables
-40x^2-7x+20=0
a = -40; b = -7; c = +20;
Δ = b2-4ac
Δ = -72-4·(-40)·20
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-57}{2*-40}=\frac{-50}{-80} =5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+57}{2*-40}=\frac{64}{-80} =-4/5 $
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