(-5/x)=(11/3x)-6

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Solution for (-5/x)=(11/3x)-6 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

-5/x = (11/3)*x-6 // - (11/3)*x-6

6-((11/3)*x)-5/x = 0

(-11/3)*x-5/x+6 = 0

6*x^0-11/3*x^1-5*x^-1 = 0

(6*x^1-11/3*x^2-5*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^1-11/3*x^2-5*x^0) = 0

x^1

(-11/3)*x^2+6*x-5 = 0

(-11/3)*x^2+6*x-5 = 0

DELTA = 6^2-(-5*4*(-11/3))

DELTA = -112/3

DELTA < 0

x in { }

x belongs to the empty set

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