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(-5/6x)-(2/3x)=-24
We move all terms to the left:
(-5/6x)-(2/3x)-(-24)=0
Domain of the equation: 6x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(-5/6x)-(+2/3x)-(-24)=0
We add all the numbers together, and all the variables
(-5/6x)-(+2/3x)+24=0
We get rid of parentheses
-5/6x-2/3x+24=0
We calculate fractions
(-15x)/18x^2+(-12x)/18x^2+24=0
We multiply all the terms by the denominator
(-15x)+(-12x)+24*18x^2=0
Wy multiply elements
432x^2+(-15x)+(-12x)=0
We get rid of parentheses
432x^2-15x-12x=0
We add all the numbers together, and all the variables
432x^2-27x=0
a = 432; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·432·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*432}=\frac{0}{864} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*432}=\frac{54}{864} =1/16 $
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