(-3z-2)/25

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Solution for (-3z-2)/25 equation: 


z in (-oo:+oo)

(-3*z-2)/2 < 5 // - 5

(-3*z-2)/2-5 < 0

(-3*z-2)/2+(-5*2)/2 < 0

-3*z-5*2-2 < 0

-3*z-12 < 0

(-3*z-12)/2 < 0

(-3*z-12)/2 < 0 // * 2^2

2*(-3*z-12) < 0

( -3*z-12 )

-3*z-12 < 0 // + 12

-3*z < 12 // : -3

z > 12/(-3)

z > -4

( 2 )

2 < 0

z belongs to the empty set

	(-oo:-4)	(-4:+oo)
-3*z-12	+	-
2	+	+


z in (-4:+oo)

(-4:+oo)

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