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(-3x-1)(x-6)=0
We multiply parentheses ..
(-3x^2+18x-1x+6)=0
We get rid of parentheses
-3x^2+18x-1x+6=0
We add all the numbers together, and all the variables
-3x^2+17x+6=0
a = -3; b = 17; c = +6;
Δ = b2-4ac
Δ = 172-4·(-3)·6
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-19}{2*-3}=\frac{-36}{-6} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+19}{2*-3}=\frac{2}{-6} =-1/3 $
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