(-3m-2)-3(-2m-2)=2(3m+1)+5(-m+2)

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Solution for (-3m-2)-3(-2m-2)=2(3m+1)+5(-m+2) equation: 



(-3m-2)-3(-2m-2)=2(3m+1)+5(-m+2)

We move all terms to the left:

(-3m-2)-3(-2m-2)-(2(3m+1)+5(-m+2))=0

We add all the numbers together, and all the variables

(-3m-2)-3(-2m-2)-(2(3m+1)+5(-1m+2))=0

We multiply parentheses

(-3m-2)+6m-(2(3m+1)+5(-1m+2))+6=0

We get rid of parentheses

-3m+6m-(2(3m+1)+5(-1m+2))-2+6=0



We calculate terms in parentheses: -(2(3m+1)+5(-1m+2)), so:

2(3m+1)+5(-1m+2)

We multiply parentheses

6m-5m+2+10

We add all the numbers together, and all the variables

m+12

Back to the equation:

-(m+12)



We add all the numbers together, and all the variables

3m-(m+12)+4=0

We get rid of parentheses

3m-m-12+4=0

We add all the numbers together, and all the variables

2m-8=0

We move all terms containing m to the left, all other terms to the right

2m=8

m=8/2

m=4

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