(-3d+8)(3d-10)=0

Solution for (-3d+8)(3d-10)=0 equation:

(-3d+8)(3d-10)=0

We multiply parentheses ..

(-9d^2+30d+24d-80)=0

We get rid of parentheses

-9d^2+30d+24d-80=0

We add all the numbers together, and all the variables

-9d^2+54d-80=0

a = -9; b = 54; c = -80;
Δ = b2-4ac
Δ = 542-4·(-9)·(-80)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6}{2*-9}=\frac{-60}{-18}
=3+1/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6}{2*-9}=\frac{-48}{-18}
=2+2/3
$